Convert Sorted Array to Binary Search Tree
Total Accepted: 61516 Total Submissions: 173462 Difficulty: Medium
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: TreeNode* sortedArrayToBST(vector & nums,int start,int end){ if(end <= start) return NULL; int mid = start + (end-start)/2; TreeNode* root = new TreeNode(nums[mid]); root->left = sortedArrayToBST(nums,start,mid); root->right = sortedArrayToBST(nums,mid+1,end); return root; } TreeNode* sortedArrayToBST(vector & nums) { int nums_size = nums.size(); return sortedArrayToBST(nums,0,nums_size); }};
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